- The principle that amounts to Rs. 4913 in 3 years at 6 1/4 % per annum C.I. compounded annually, is?

A. Rs. 3096

B. Rs. 4076

C. Rs. 4085

D. Rs. 4096 - Find the Compound Interest on Rs.8000 at 5% per annum for 3 years when C.I is reckoned yearly?

A. Rs. 1,185

B. Rs. 1,261

C. Rs. 1,346

D. Rs. 1,440 - The difference between simple interest and C.I. at the same rate for Rs.5000 for 2 years in Rs.72. The rate of interest is?

A. 6%

B. 8%

C. 10%

D. 12% - The difference between compound and simple interest on a certain sum of money for 3 years at 6 2/3% p.a is Rs.184. Find the sum?

A. Rs.12,000

B. Rs.13,500

C. Rs.14,200

D. Rs.17,400 - A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.482 more if the interest were payable half-yearly, then it were pay able yearly. Find the sum.

A. Rs.1,000

B. Rs.1,250

C. Rs.2,000

D. Rs.4,000 - The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?

A. Rs.3,000

B. Rs.3,300

C. Rs.3,600

D. Rs.3,900 - Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?

A. Rs.9,021

B. Rs.9,162

C. Rs.9,261

D. Rs.9,621 - Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?

A. Rs.61,000

B. Rs.65,000

C. Rs.71,000

D. Rs.81,000 - Indu gave Bindu Rs.1250 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?

A. Rs.10

B. Rs.5

C. Rs.3

D. Rs.2 - How much more would Rs.20000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?

A. Rs.424

B. Rs.482

C. Rs.512

D. Rs.842

According to the formula,

Principle = [4913 / (1 + 25/ (4 * 100))3]

=> 4913 * 16/17 * 16/17 * 16/17 = Rs. 4096

A = 8000(21/20)^3 = 9261

Now, 9261 - 8000 = Rs. 1,261

5000 = 72(100/R)^2

5 R^2 = 720 => R = 12

P = (184*10^6) / [6 2/3 * 6 2/3 *(300*6 2/3)]

P = 13500

P(11/10)^4 - P(6/5)^2 = 482

P = 2000

P = 144(100/5)^2 => P = 3600

A = 8000(21/20)^3 = 9261

64000* 9/8 * 9/8 = 81000

1250 = D(100/4)^2

D = 2

20000(11/10)^4 - 20000(6/5)^2 = 482

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