For instance, when Founders present their pitches to his or her potential investors, they do that by interpreting the data such as market size, growth rate and so on for better understanding. There are 2 principal methods by which data interpretation can be done:

- Qualitative Methods
- Quantitative Methods

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There are 2 main types of qualitative data, such as nominal and ordinal data. These two data types are both performed using the same method, but ordinal data interpretation is easier than that of nominal data.

In most of the cases, ordinal data is usually labeled with numbers throughout the process of data collection and so many times coding may not be required. This is different from nominal data which still requires to be coded for proper interpretation.

Due to its natural existence as a number, analysts do not need to use the coding method on quantitative data before analyzing it. The process of analyzing quantitative data requires statistical modeling techniques namely standard deviation, mean and median.

A) 100

B) 101

C) 102

D) 103

E) None of the above

**Answer:** Option C
**Explanation:** School A: B+G = 10035

B-G = 373

Girls = 4831

In School B: B+G = 10098

B-G = 640

G = 4729

Difference = 102
**Question 2:** Girls in School C forms approximately what percent of the total number students in that School?

A) 45.5%

B) 47.5%

C) 48.5%

D) 49.5%

E) 50%

**Answer:** Option C
**Explanation:** B+G = 10087

B-G = 285

G = 4901

% = 4901/10087 = 48.58%
**Question 3:** What is the ratio of Sum of Boys in School D and Girls in School E together to the Sum of Girls in School D and Boys in School E together is?

A) 997:1012

B) 999:1012

C) 1000:1011

D) 1000:1013

E) None of the above

**Answer:** Option A
**Explanation:** School D: B+G = 10081

B-G = 475

B = 5278 G = 4803

In School E: B+G = 10009

B-G = 625

B = 5317 G = 4692

Ratio = (5278+4692):(4803+5317)

9970:10120

997:1012
**Question 4:** How many number of Boys are there in School F?

A) 5134

B) 5234

C) 5334

D) 5444

E) None of the above

**Answer:** Option B
**Explanation:** B+G = 10045

B-G = 423

Boys = 5234
**Question 5:** In which of the following School least no of Girls are present?

A) School A

B) School B

C) School C

D) School D

E) School E

**Answer:** Option E
**Explanation:** From above calculations:

School A: 4831

School B: 4729

School C: 4901

School D: 4803

School E: 4692

A) 13

B) 14

C) 15

D) 16

E) None of the above

**Answer:** Option B
**Explanation:** Monday Cakes sold = 84*11.5 = 966

Ratio of Vanilla: Chocolate = 2:1

Vanilla = 644

Wednesday: 1050

Ratio of Vanilla: Chocolate = 3:2

Vanilla = 630
**Question 7:** If the ratio of Vanilla Cakes Sold on Thursday to Vanilla Cakes sold on Saturday is 3:4, Number of Chocolate Cakes Sold on Thursday is equal to Number of Chocolate on Saturday then Number of Chocolate Cakes sold on Saturday is equal to total number of Cakes sold on which day?

A) Monday

B) Tuesday

C) Wednesday

D) Thursday

E) Friday

**Answer:** Option A
**Explanation:** Thursday = V1+C = 1218

Saturday = V2+ C = 1302

V2-V1 = 84

V1:V2 = 3:4

V1 = 252 V2 = 336

Then, C = 996 = 84*11.5 =i.e., Total Cakes sold on Monday.
**Question 8:** If the average number of Vanilla Cakes Sold on Friday and Sunday are 858 and Number of Chocolate Cakes Sold on Sunday are 72 more than Number of Chocolate Cakes sold on Friday then Number of Chocolate Cakes sold on Friday is?

A) 482

B) 492

C) 498

D) 512

E) None of the above

**Answer:** Option B
**Explanation:** Friday = 1344 = V1+C1

Sunday = 1428 = V2+C2

Average = (V1+V2)/2 = 858 then V1+V2 = 1716

2772 = 1716+C1+C2

C1+C2 = 1056

C2-C1 = 72

C1 = 492 = Friday Chocolate Cakes
**Question 9:** Ratio of Vanilla Cakes Sold to Chocolate Cakes Sold is 46:45 on Tuesday then how many number of Vanilla Cakes are Sold on that day?

A) 540

B) 546

C) 552

D) 562

E) None of the above

**Answer:** Option C
**Explanation:** Cakes = 84*13 = 1092

Vanilla = 1092*46/91 = 552
**Question 10:** If the ratio of Vanilla Cakes sold to Chocolate Cakes sold on Monday is 2:1 and the ratio of Selling Price of Vanilla Cake to Chocolate Cake is the 1:4, total amount earned by him on Monday is Rs.9660 then what is the rate of One Vanilla Cake?

A) Rs 4

B) Rs 5

C) Rs 10

D) Rs 20

E) None of the above

**Answer:** Option B
**Explanation:** Vanilla = 966*2/3 = 644

Chocolate = 966*1/3 = 322

R1:R2 = 1:4

644R1+322R2 = 9660

R1 = 5

A) 6%

B) 5%

C) 3%

D) 4%

E) 9%

**Answer:** Option E
**Explanation:**

Savings Scheme |
Vikram and Deepa’s Investment |
Vikram’s Investment |
Deepa’s Investment |

A | 84000 | 43680 | 40320 |

B | 72000 | 43200 | 28800 |

C | 32000 | 12800 | 19200 |

D | 60000 | 18000 | 42000 |

E | 64000 | 25600 | 38400 |

F | 96000 | 61440 | 34560 |

R² = D×(100)2/P

R = √D×(100)2/P = √349.92×100×100/43200

R = 9%

A) 12,364

B) 12,096

C) 12,242

D) 12,542

E) 12,112

**Answer:** Option B
**Explanation:** The interest earned by Deepa after 4 years = 34560×7×2/100 + 34560 (1+10/100)²-34560

= 34560×7×2/100+34560(121-100/100)

= 34560/100(14+21)

= 12096/-
**Question 13:** What is the respective ratio between the total amount invested by Vikram in scheme C and E together and the total amount invested by Deepa in the same savings scheme together?

A) 3:2

B) 3:4

C) 1:4

D) 2:3

E) 3:1

**Answer:** Option D
**Explanation:** Required Ratio = (12800+2560) : (19200+38400)

= 38400 : 57600

= 2:3
**Question 14:** Savings Scheme A offers simple interest at a certain rate of interest (p.c.p.a.). If the difference between the interests earned by Vikram and Deepa from Savings Scheme A after 4 years is Rs.4435.50, what is the rate of interest (p.c.p.a)?

A) 15%

B) 23%

C) 33%

D) 24%

E) 25%

**Answer:** Option C
**Explanation:** 43680×R×4/100-40320×R×4/100 = 4436.520

13440R = 4436.520×100

R = 443652/13440

= 33%
**Question 15:** What is the average amount invested by Vikram in savings schemes A, B, C, D and E together?

A) Rs. 29,248/-

B) Rs. 30,562/-

C) Rs. 31,126/-

D) Rs. 29,688/-

E) Rs. 28,656/-

**Answer:** Option E
**Explanation:** Required average amount = 43680 + 43200 + 12800 + 18000 + 25600 / 5

= Rs. 28656/-
**Question 16:** What is the difference between the average amount invested in Savings schemes A, B, D and E by Vikram and the average amount invested in Savings schemes B, C, E and F by Deepa?

A) 2540

B) 2760

C) 2560

D) 2320

E) 2380

**Answer:** Option E
**Explanation:** Average amount invested in schemes A, B, D and E by Vikram = (43680 + 43200 + 18000 + 25600)/4 = 90240/4 = 32620

Average amount invested in schemes B, C, E and F by Deepa = (28800 + 19200 + 38400 + 34560)/4 = 119680/4 = 30240

Difference = 32620 – 30240 = 2380

Time taken by the pipes to fill a tank/cistern (hours/minutes)

A) 6.5 minutes

B) 7.5 minutes

C) 8.5 minutes

D) 9.5 minutes

E) None of the above

**Answer:** Option B
**Explanation:** Part filled by P and Q = 1/15 + 1/10 = 1/6

Part filled by Q = 1/10

x/2(1/6 + 1/10) = 2/15 = 15/2 = 7.5 minutes
**Question 18:** Two pipes M and N can fill a tank. If both the pipes are opened simultaneously, after how much time should N be closed so that the tank is full in 8 minutes?

A) 14 minutes

B) 12 minutes

C) 15 minutes

D) 18 minutes

E) None of the above

**Answer:** Option D
**Explanation:** Required time = y(1-(t/x)) = 27(1-(8/24)) = 18 minutes
**Question 19:** Three pipe E, F and R can fill a tank. If Pipe R alone can fill a tank in 24 minutes then the pipe R is closed 12 minutes before the tank is filled. Then, in what time the tank is full?

A) 8.(5/13)

B) 8.(4/13)

C) 7.(4/13)

D) 8.(6/13)

E) None of the above

**Answer:** Option B
**Explanation:** Let T is the time taken by the pipes to fill the tank

(1/12 + 1/18 + 1/24)*(T – 12) + (1/12 + 1/18)*12 = 1

We will get T = 108/13 = 8.(4/13)
**Question 20:** Two pipes C and D can fill a cistern. If they are opened on alternate minutes and if pipe C is opened first, in how many minutes will the tank be full?

A) 4 minutes

B) 5 minutes

C) 2 minutes

D) 6 minutes

E) None of the above

**Answer:** Option D
**Explanation:** Pipe P can fill = 1/12

Pipe Q can fill = 1/4

For every two minutes, 1/12 + 1/4 = 1/3 Part filled

Total = 6 minutes
**Question 21:** Two pipes, A and B are opened simultaneously and it is found that due to the leakage in the bottom, 17/7 minutes are taken extra to fill the tank. If the tank is full, in what approximate time would the leak empty it?

A) 27 minutes

B) 32 minutes

C) 36 minutes

D) 39 minutes

E) None of the above

**Answer:** Option D
**Explanation:** Total time taken by both pipes before the leak was developed = 60/7 minutes

now, leaks is developed which will take T time to empty the tank so, (1/15 +1/20 – 1/T) = 1/11

solve for T, we will get 660/17 minutes = 39 minutes (approx.)
**Question 22:** A waste pipe, W can carry off 12 litre of water per minute. If all the pipes I, J and W are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.

A) 30 ltrs

B) 45 ltrs

C) 60 ltrs

D) 75 ltrs

E) None of the above

**Answer:** Option C
**Explanation:** Let the waste pipe take ‘T’ time to empty the tank.

(1/10 + 1/12 – 1/T)*60 = -1

We will get T = 5 min

So capacity = 5*12 = 60 ltrs
**Question 23:** Two pipes E and F are opened simultaneously and it is found that due to leakage in the bottom of the tank it took 48 minutes excess time to fill the cistern. When is the cistern full, in what time will the leak empty it?

A) 72 hours

B) 62 hours

C) 64 hours

D) 84 hours

E) None of the above

**Answer:** Option A
**Explanation:** Work done by the two pipes in 1 hour = (1/12)+(1/18) = (15/108).

Time taken by these pipes to fill the tank = (108/15)hrs = 7 hours 12 min.

Due to leakage, time taken = 7 hours 12 min + 48 min = 8 hours

Work done by two pipes and leak in 1 hour = 1/8.

Work done by the leak in 1 hour =(15/108)-(1/8)=(1/72).

Leak will empty the full cistern in 72 hours.
**Question 24:** Three pipes C, A and B can fill a tank. If pipe C is opened all the time and pipe A and B are opened for one hour alternatively. The tank will be full in

A) 5 hrs

B) 6 hrs

C) 7 hrs

D) 8 hrs

E) None of the above

**Answer:** Option C
**Explanation:** (1/12 + 1/15) + (1/12 + 1/20) = 17/60 (in 2 hrs this much tank is filled)

so in 6 hrs 51/60 is filled. Remaining, 9/60 = (1/12 + 1/15)*t, so T = 1hr

so total = 6 + 1 = 7 hrs

A) Rs. 360

B) Rs. 385

C) Rs. 240

D) Can’t be determined

E) None of the above

**Answer:** Option C
**Explanation:** Efficiency of P = 4%

Efficiency of R = 2%

[(4+2)*10] = 60%

The remaining work was done by U = 40%.

40% of 600 = 240
**Question 26:** Q and S work together for 5 days, the rest of the work is finished by M in two more days. If they get Rs. 6000 as wages for the whole work, what are the daily wages of Q, S and M respectively?

A) 200, 250, 300

B) 300, 200, 250

C) 600, 400, 200

D) 600, 400, 500

E) None of the above

**Answer:** Option D
**Explanation:** Q’s 5 days work = 50%

S’s 5 days work = 33.33%

M’s 2 days work = 16.66% [100- (50+33.33)] Ratio of work of Q, S and M = 3: 2: 1

Q’s total share = Rs. 3000

S’s total share = Rs. 2000

M’s total share = Rs. 1000

Q’s one day’s wage = Rs. 600

S’s one day’s wage = Rs. 400

M’s one day’s wage = Rs. 500
**Question 27:** The efficiency of L is 25% more than P. L started a work alone and then P joined her 5 days before actual completion of the work. For how many days L worked alone?

A) 9

B) 11

C) 10

D) 25

E) 12

**Answer:** Option B
**Explanation:** Efficiency (L : P) = 5 : 4

Number of days(L : P) = 4x : 5x = 4x : 25

∴ Number of days required by L to finish the work alone = 4x

= 4 x 5 = 20.

L and P work together for last 5 days = 5 x 9 = 45%

Efficiency of L = 5% and P’s efficiency = 4%

∴ No. of days taken by L to complete 55% work = 55/5 = 11days
**Question 28:** R started the work and left after some days, when 25% work was don

E) After it Z joined and completed it working for 25 days. In how many days R and Z can do the complete work, working together?

A) 6

B) 8

C) 10

D) 12

E) 20

**Answer:** Option E
**Explanation:** Efficiency of R = (100/50) = 2%

Rest work = 75%

∴ Efficiency of Z = 75/25 = 3%

∴ Combined efficiency of R and Z = 5%

∴ Number of days required by R and Z to work together = 100/5 = 20 days.
**Question 29:** T and V started the work. After 3 days Z joined them, who can complete alone the same whole work in 3 days. What is the total number of days in which they had completed the work?

A) 12

B) 8

C) 4

D) 6

E) None of the above

**Answer:** Option C
**Explanation:** Efficiency of T and V = 11.11 + 5.55 = 16.66%

Work done in 3 days = 3 x 16.66 = 50%

Rest work done by T, V and Z = 50/50 = 1 day

Work can be completed in 4 days.
**Question 30:** A is twice efficient as B and together they do the same work in as much time as T and V together. In how many days A can complete the work individually?

A) 5 days

B) 8 days

C) 4 days

D) 9 days

E) None of the above

**Answer:** Option D
**Explanation:** 1/x + 1/2x = 1/9 + 1/18

3/2x = 3/18

Number of days taken by A = 9 days
**Question 31:** After working for 3 days S is joined by O. If they complete the remaining work in 3 more days, in how many days can O alone complete the work?

A) 10 days

B) 8 days

C) 5 days

D) 12 days

E) 15 days

**Answer:** Option C
**Explanation:** Total days S worked = 3+3 = 6

6/15 = 2/5

So 3/5 = 3/x

x = 5
**Question 32:** X can do a certain work in the same time in which Y and R together can do it. If X and Y together could do it in the same time as that of Q then Y alone could do it in:

A) 15 days

B) 20 days

C) 25 days

D) 30 days

E) 35 days

**Answer:** Option C
**Explanation:** X, Y and R’s 1 day work = 1/10 + 1/50 = 6/50 = 3/25

X’s 1 day work = Y + R‘s 1 day work

2*( x’s 1 day work) = 3/25

x’s 1 day work = 3/50

Y’s 1 day work = 1/10 – 3/50 = 2/50 = 1/25

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