Aptitude Questions on Train Problems

  1. A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
    A. 69 secs
    B. 79 secs
    C. 89 secs
    D. 99 secs
  2. C. 89 secs
    Speed = (240/24) m/sec = 10 m/sec
    Therefore, required time = (240 + 650)/10 sec = 89 secs
  3. A train running at certain speed crosses a stationary engine in 20 seconds. To find out the speed of the train. Which of the following information is necessary:
    A. Only the length of the train
    B. Only the length of the engine
    C. Either the length of the train and the length of the engine
    D. Both the length of the train and the length of the engine
  4. D. Both the length of the train and the length of the engine
    Since the sum of the lengths of the train and the length of the engine is needed, So both the lengths must be known.
  5. A train moves with the speed of 180 km.hr then its speed in meters per second is:
    A. 20 m/sec
    B. 30 m/sec
    C. 40 m/sec
    D. 50 m/sec
  6. D. 50 m/sec
    180 km/hr = (180 × 5/18)m/sec = 50 m/sec
  7. A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
    A. 12 secs
    B. 18 secs
    C. 36 secs
    D. 72 secs
  8. C. 36 secs
    Speed of train relative to jogger = 45 - 9 = 36 km/hr.
    = 36 * 5/18 = 10 m/sec
    Distance to be covered = 240 + 120 = 360 m
    Time taken = 360/10 = 36 secs
  9. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
    A. 1 : 3
    B. 3 : 2
    C. 3 : 4
    D. None of these
  10. B. 3 : 2
    Let the speeds of the two trains be x m/sec and y m/sec respectively.
    Then, length of the first train = 27 x meters, and length of the second train = 17 y meters.
    (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y
    => 4 x = 6 y
    => x/y = 3/2
  11. The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
    A. 225 m
    B. 235 m
    C. 245 m
    D. 255 m
  12. C. 245 m
    Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec.
    Let the length of bridge be x meters.
    Then, (130 + X)/30 = 25/2
    => 2(130 + X) = 750
    => X = 245 m
  13. A train 100 m long crosses a platform 125 m long in 15 sec. Find the speed of the train?
    A. 45 kmph
    B. 50 kmph
    C. 54 kmph
    D. 60 kmph
  14. C. 54 kmph
    D = 100 + 125 = 225
    T = 15
    S = 225/15 * 18/5 = 54 kmph
  15. Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. In how much time will the trains cross each other?
    A. 20/7 secs
    B. 57/7 secs
    C. 60/7 secs
    D. 80/7 secs
  16. D. 80/7 secs
    Relative speed = (54 + 72)* 5/18 = 7 * 5 = 35 mps
    The time required = d/s = (100 + 100 + 200)/35
    =>400/35 = 80/7 secs
  17. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
    A. 120 metres
    B. 150 metres
    C. 180 metres
    D. 210 metres
  18. B. 150 metres
    Speed=(60 * 5/18) = (50/3)
    Length of the train = (Speed * Time) = (50/3 * 9) = 150 metres
  19. A train sets off at 2:00 pm at the speed of 70 kmph. Another train starts at 3:30 pm in the same direction at the rate of 85 kmph. At what time the trains will meet?
    A. 8:30 pm
    B. 9:30 pm
    C. 10:30 pm
    D. 10:45 pm
  20. C. 10:30 pm
    D = 70 * 1 1/2 = 105 km
    RS = 85 – 70 = 15
    T = 105/15 = 7 h
    3:30 + 7 h = 10:30 pm